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Programing session Armstrang Number
Armsrong Number:- The armstrong number is a number that is equal in sum of own digit number raisid to the power of number in digit . then it is a armstrong number . *Example: * For a 3-digit number, if the sum of each digit raised to the power of 3 is equal to the original number, then it is an Armstrong number. For instance: 153 is an Armstrong number because: no = 153 rem = no % 10 (1*1*1)(5*5*5)(3*3*3) =1+125+27 =153 *For example: * $ Following the method. $ first of look the board start step by step explain: step 1:- No = 153 Arm = 0 Rem = No % 10 Arm = Arm + (Rem*Rem*Rem) =0+(3*3*3) => 27 -------------------> Arm No = No/10 =153/10 =>15 step 2:- No = 15 Arm = 27 Rem = No % 10 Arm = Arm + (Rem*Rem*Rem) =27+(5*5*5) => 152 -------------------> Arm No = No/10 =15/10 =>1 step 3:- No = 1 Arm = 152 Rem = No % 10 Arm = Arm + (Rem*Rem*Rem) =152+(1*1*1) => 153 -------------------> Arm No = No/10 Armstrang: =1/10 =>0 no>0 -----> condition false loop stop. 1 3
Armsrong Number:-
The armstrong number is a number that is equal in sum of own digit number raisid to the power of number in digit . then it is a armstrong number .
*Example: *
For a 3-digit number, if the sum of each digit raised to the power of 3 is equal to the original number, then it is an Armstrong number.
For instance:
153 is an Armstrong number because:
no = 153
rem = no % 10
(1*1*1)(5*5*5)(3*3*3)
=1+125+27
=153
*For example: *
$ Following the method.
$ first of look the board start
step by step explain:
step 1:-
No = 153
Arm = 0
Rem = No % 10
Arm = Arm + (Rem*Rem*Rem)
=0+(3*3*3)
=> 27 -------------------> Arm
No = No/10
=153/10
=>15
step 2:-
No = 15
Arm = 27
Rem = No % 10
Arm = Arm + (Rem*Rem*Rem)
=27+(5*5*5)
=> 152 -------------------> Arm
No = No/10
=15/10
=>1
step 3:-
No = 1
Arm = 152
Rem = No % 10
Arm = Arm + (Rem*Rem*Rem)
=152+(1*1*1)
=> 153 -------------------> Arm
No = No/10
Armstrang:
=1/10
=>0
no>0 -----> condition false loop stop.
1
3
